5v^2-27+4=-6

Solution for 5v^2-27+4=-6 equation:

5v^2-27+4=-6

We move all terms to the left:

5v^2-27+4-(-6)=0

We add all the numbers together, and all the variables

5v^2-17=0

a = 5; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·5·(-17)
Δ = 340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{340}=\sqrt{4*85}=\sqrt{4}*\sqrt{85}=2\sqrt{85}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{85}}{2*5}=\frac{0-2\sqrt{85}}{10}
=-\frac{2\sqrt{85}}{10}
=-\frac{\sqrt{85}}{5}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{85}}{2*5}=\frac{0+2\sqrt{85}}{10}
=\frac{2\sqrt{85}}{10}
=\frac{\sqrt{85}}{5}
$